JAVASCRIPT   25
ajaxQuery
Guest on 7th March 2023 12:09:11 AM


  1. function ajaxQuery(url) {
  2.     if (adtest == 'on') return false;
  3.     xmlHttp = getXMLhttp();
  4.     if (!xmlHttp) return ajaxBackfill(url);
  5.     xmlHttp.open("GET", url, false);
  6.     return xmlHttp.send(null);
  7. }
Raw Paste

Login or Register to edit or fork this paste. It's free.